Google Search

Custom Search

Sunday, February 14, 2010

10 Challenging Star Pattern Programs in C

Computer languages are not as easy as human languages, they need you to become a computer yourself, think like a computer and write an algorithm. Computer programs are fun if you take them up as a challenge, as unsolved puzzles. There is lot of fun in taking up the challenge, understanding the problem, writing an algorithm, writing a program and most importantly running the program and obtaining required output.
Here are few challenging C program questions for you. Let’s see how many of them you would be able to write without seeing the program solution given below. These questions are to print patterns using asterisk(star) character. Comment below if you have tougher pattern questions.

  1. Write a C program to print the following pattern:
    *
    * *
    * * *
    * * * *
  2. Write a C program to print the following pattern:
    *                   *
    * * * * * *
    * * * * * * * * * *
    * * * * * * * * * * *
  3. Write a C program to print the following pattern:
    *                         *
    * *
    * * * *
    * * * *
    * * * * *
    * * * *
    * * * *
    * *
    * *
  4. Write a C program to print the following pattern:
    *   *   *   *   *
    * * * *
    * * *
    * *
    *
    * *
    * * *
    * * * *
    * * * * *
  5. Write a C program to print the following pattern:
    *
    * * *
    * * * * *
    * * * * * * *
    * * * * * * * * *
    * * * * * * *
    * * * * *
    * * *
    *
    * * *
    * * * * *
  6. Write a C program to print the following pattern:
    *
    * *
    * * *
    * * * *
    * * *
    * *
    *
  7. Write a C program to print the following pattern:
    * * * * * * * * *
    * * * * * * * *
    * * * * * *
    * * * *
    * *
    * * * *
    * * * * * *
    * * * * * * * *
    * * * * * * * * *
  8. Write a C program to print the following pattern:
    * * * * * * * * * * * * * * * * *
    * * * * * * * * * * * * * *
    * * * * * * * * * *
    * * * * * *
    * * * * * * * * *
    * * * * * * *
    * * * * *
    * * *
    *
  9. Write a C program to print the following pattern:
    *
    * * *
    * * * * *
    * * * * * * *
    * *
    * * * *
    * * * * * *
    * * * * * * *
    * * * * * *
    * * * *
    * *
    * * * * * * *
    * * * * *
    * * *
    *
  10. Write a C program to print the following pattern:
    * * * * * * * * * * * * * * * * * * * * * * * * *
    * * * * * *
    * * * * * *
    * * * * * *
    * * *
    * * * * * *
    * * * * * *
    * * * * * *
    * * * * * * * * * * * * * * * * * * * * * * * * *
  1. Write a C program to print the following pattern:
  2. *
    * *
    * * *
    * * * *
    Program:
    /* This is a simple mirror-image of a right angle triangle */

    #include
    int main() {
    char prnt = '*';
    int i, j, nos = 4, s;
    for (i = 1; i <= 5; i++) {
    for (s = nos; s >= 1; s--) { // Spacing factor
    printf(" ");
    }
    for (j = 1; j <= i; j++) {
    printf("%2c", prnt);
    }
    printf("\n");
    --nos; // Controls the spacing factor
    }
    return 0;
    }
    Download Code
  3. Write C program to print the following pattern:
    *                   *
    * * * * * *
    * * * * * * * * * *
    * * * * * * * * * * *
  4. Program:
    #include
    int main() {
    char prnt = '*';
    int i, j, k, s, c = 1, nos = 9;
    for (i = 1; c <= 4; i++) {
    // As we want to print the columns in odd sequence viz. 1,3,5,.etc
    if ((i % 2) != 0) {
    for (j = 1; j <= i; j++) {
    printf("%2c", prnt);
    }
    for (s = nos; s >= 1; s--) { //The spacing factor
    if (c == 4 && s == 1) {
    break;
    }
    printf(" ");
    }
    for (k = 1; k <= i; k++) {
    if (c == 4 && k == 5) {
    break;
    }
    printf("%2c", prnt);
    }
    printf("\n");
    nos = nos - 4; // controls the spacing factor
    ++c;
    }
    }
    return 0;
    }
    Download Code
  5. Write C program to print the following pattern:
    *                         *
    * *
    * * * *
    * * * *
    * * * * *
    * * * *
    * * * *
    * *
    * *
  6. Program:
    #include
    int main() {
    char prnt = '*';
    int i, j, k, s, p, r, nos = 7;

    for (i = 1; i <= 5; i++) {
    for (j = 1; j <= i; j++) {
    if ((i % 2) != 0 && (j % 2) != 0) {
    printf("%3c", prnt);
    }
    else if ((i % 2) == 0 && (j % 2) == 0) {
    printf("%3c", prnt);
    }
    else {
    printf(" ");
    }
    }
    for (s = nos; s >= 1; s--) { // for the spacing factor
    printf(" ");
    }
    for (k = 1; k <= i; k++) { //Joining seperate figures
    if (i == 5 && k == 1) {
    continue;
    }
    if ((k % 2) != 0) {
    printf("%3c", prnt);
    }
    else {
    printf(" ");
    }
    }
    printf("\n");
    nos = nos - 2; // space control
    } nos = 1; // remaining half..
    for (p = 4; p >= 1; p--) {
    for (r = 1; r <= p; r++) {
    if ((p % 2) != 0 && (r % 2) != 0) {
    printf("%3c", prnt);
    }
    else if ((p % 2) == 0 && (r % 2) == 0) {
    printf("%3c", prnt);
    }
    else {
    printf(" ");
    }
    }
    for (s = nos; s >= 1; s--) {
    printf(" ");
    }
    for (k = 1; k <= p; k++) {
    if ((k % 2) != 0) {
    printf("%3c", prnt);
    }
    else {
    printf(" ");
    }
    }
    nos = nos + 2; // space control
    printf("\n");
    }
    return 0;
    }
    Download Code
Explanation: This can be seen as an inverted diamond composed of stars. It can be noted that the composition of this figure follows sequential pattern of consecutive stars and spaces. In case of odd row number, the odd column positions will be filled up with ‘*’, else a space will be spaced and vice-versa in case of even numbered row. In order to achieve this we will construct four different right angle triagles aligned as per the requirement.
  1. Write a C program to print the following pattern:
    *   *   *   *   *
    * * * *
    * * *
    * *
    *
    * *
    * * *
    * * * *
    * * * * *
  2. Program:
    #include
    int main() {
    char prnt = '*';
    int i, j, s, nos = 0;
    for (i = 9; i >= 1; (i = i - 2)) {
    for (s = nos; s >= 1; s--) {
    printf(" ");
    }
    for (j = 1; j <= i; j++) {
    if ((i % 2) != 0 && (j % 2) != 0) {
    printf("%2c", prnt);
    } else {
    printf(" ");
    }
    }
    printf("\n");
    nos++;
    }
    nos = 3;
    for (i = 3; i <= 9; (i = i + 2)) {
    for (s = nos; s >= 1; s--) {
    printf(" ");
    }
    for (j = 1; j <= i; j++) {

    if ((i % 2) != 0 && (j % 2) != 0) {
    printf("%2c", prnt);
    } else {
    printf(" ");
    }
    }
    nos--;
    printf("\n");
    }
    return 0;
    }
    Download Code
  3. Write a C program to print the following pattern:
    *
    * * *
    * * * * *
    * * * * * * *
    * * * * * * * * *
    * * * * * * *
    * * * * *
    * * *
    *
    * * *
    * * * * *
  4. Program:
    #include
    int main() {
    char prnt = '*';
    int i, j, k, s, nos = 4;
    for (i = 1; i <= 5; i++) {
    for (s = nos; s >= 1; s--) {
    printf(" ");
    }
    for (j = 1; j <= i; j++) {
    printf("%2c", prnt);
    }
    for (k = 1; k <= (i - 1); k++) {
    if (i == 1) { continue;
    }
    printf("%2c", prnt);
    }
    printf("\n"); nos--;
    }
    nos = 1;
    for (i = 4; i >= 1; i--) {
    for (s = nos; s >= 1; s--) {
    printf(" ");
    }
    for (j = 1; j <= i; j++) {
    printf("%2c", prnt);
    }
    for (k = 1; k <= (i - 1); k++) {
    printf("%2c", prnt);
    }
    nos++;
    printf("\n");
    }
    nos = 3;
    for (i = 2; i <= 5; i++) {
    if ((i % 2) != 0) {
    for (s = nos; s >= 1; s--) {
    printf(" ");
    }
    for (j = 1; j <= i; j++) {
    printf("%2c", prnt);
    }
    }
    if ((i % 2) != 0) {
    printf("\n");
    nos--;
    }
    }
    return 0;
    }
    Download Code
  5. Write a C program to print the following pattern:
    *
    * *
    * * *
    * * * *
    * * *
    * *
    *
  6. Program:
    /*
    This can be seen as two right angle triangles sharing the same base
    which is modified by adding few extra shifting spaces
    */
    #include
    // This function controls the inner loop and the spacing
    // factor guided by the outer loop index and the spacing index.
    int triangle(int nos, int i) {
    char prnt = '*';
    int s, j;
    for (s = nos; s >= 1; s--) { // Spacing factor
    printf(" ");
    }
    for (j = 1; j <= i; j++) { //The inner loop
    printf("%2c", prnt);
    }
    return 0;
    }

    int main() {
    int i, nos = 5;
    //draws the upper triangle
    for (i = 1; i <= 4; i++) {
    triangle(nos, i); //Inner loop construction
    nos++; // Increments the spacing factor
    printf("\n"); }
    nos = 7; //Draws the lower triangle skipping its base.
    for (i = 3; i >= 1; i--) {
    int j = 1;
    triangle(nos, i); // Inner loop construction
    nos = nos - j; // Spacing factor
    printf("\n");
    }
    return 0;
    }
    Download Code
  7. Write a C program to print the following pattern:
    * * * * * * * * *
    * * * * * * * *
    * * * * * *
    * * * *
    * *
    * * * *
    * * * * * *
    * * * * * * * *
    * * * * * * * * *
  8. Program:
    #include 

    int main() {
    char prnt = '*';
    int i, j, k, s, nos = -1;
    for (i = 5; i >= 1; i--) {
    for (j = 1; j <= i; j++) {
    printf("%2c", prnt);
    }
    for (s = nos; s >= 1; s--) {
    printf(" ");
    }
    for (k = 1; k <= i; k++) {
    if (i == 5 && k == 5) {
    continue;
    }
    printf("%2c", prnt);
    }
    nos = nos + 2;
    printf("\n");
    }
    nos = 5;
    for (i = 2; i <= 5; i++) {
    for (j = 1; j <= i; j++) {
    printf("%2c", prnt);
    }
    for (s = nos; s >= 1; s--) {
    printf(" ");
    }
    for (k = 1; k <= i; k++) {
    if (i == 5 && k == 5) {
    break;
    }
    printf("%2c", prnt);
    }
    nos = nos - 2;
    printf("\n");
    }
    return 0;
    }
    Download Code
  9. Write a C program to print the following pattern:
    * * * * * * * * * * * * * * * * *
    * * * * * * * * * * * * * *
    * * * * * * * * * *
    * * * * * *
    * * * * * * * * *
    * * * * * * *
    * * * * *
    * * *
    *
  10. Program:
    #include 
    int main() {
    char prnt = '*';
    int i, j, k, s, sp, nos = 0, nosp = -1;
    for (i = 9; i >= 3; (i = i - 2)) {
    for (s = nos; s >= 1; s--) {
    printf(" ");
    }
    for (j = 1; j <= i; j++) {
    printf("%2c", prnt);
    }
    for (sp = nosp; sp >= 1; sp--) {
    printf(" ");
    }
    for (k = 1; k <= i; k++) {
    if (i == 9 && k == 1) {
    continue;
    }
    printf("%2c", prnt);
    }
    nos++;
    nosp = nosp + 2;
    printf("\n");
    }
    nos = 4;
    for (i = 9; i >= 1; (i = i - 2)) {
    for (s = nos; s >= 1; s--) {
    printf(" ");
    }
    for (j = 1; j <= i; j++) {
    printf("%2c", prnt);
    }
    nos++;
    printf("\n");
    }

    return 0;
    }
    Download Code
  11. Write a C program to print the following pattern:
    *
    * * *
    * * * * *
    * * * * * * *
    * *
    * * * *
    * * * * * *
    * * * * * * *
    * * * * * *
    * * * *
    * *
    * * * * * * *
    * * * * *
    * * *
    *
  12. Program:
    #include 
    /*
    * nos = Num. of spaces required in the triangle.
    * i = Counter for the num. of charcters to print in each row
    * skip= A flag for checking whether to
    * skip a character in a row.
    *
    */
    int triangle(int nos, int i, int skip) {
    char prnt = '*';
    int s, j;
    for (s = nos; s >= 1; s--) {
    printf(" ");
    }
    for (j = 1; j <= i; j++) {
    if (skip != 0) {
    if (i == 4 && j == 1) {
    continue;
    }
    }
    printf("%2c", prnt);
    }
    return 0;
    }

    int main() {
    int i, nos = 4;
    for (i = 1; i <= 7; (i = i + 2)) {
    triangle(nos, i, 0);
    nos--;
    printf("\n");
    }
    nos = 5;
    for (i = 1; i <= 4; i++) {
    triangle(1, i, 0); //one space needed in each case of the formation
    triangle(nos, i, 1); //skip printing one star in the last row.
    nos = nos - 2;
    printf("\n");
    }
    nos = 1;
    for (i = 3; i >= 1; i--) {
    triangle(1, i, 0);
    triangle(nos, i, 0);
    nos = nos + 2;
    printf("\n");
    }
    nos = 1;
    for (i = 7; i >= 1; (i = i - 2)) {
    triangle(nos, i, 0);
    nos++;
    printf("\n");
    }
    return 0;
    }
    Download Code
  13. Write a C program to print the following pattern:
    * * * * * * * * * * * * * * * * * * * * * * * * *
    * * * * * *
    * * * * * *
    * * * * * *
    * * *
    * * * * * *
    * * * * * *
    * * * * * *
    * * * * * * * * * * * * * * * * * * * * * * * * *
  14. Program:
    #include 

    /*
    * nos = Num. of spaces required in the triangle.
    * i = Counter for the num. of characters to print in each row
    * skip= A flag for check whether to
    * skip a character in a row.
    *
    */

    int triangle(int nos, int i, int skip) {
    char prnt = '*';
    int s, j;
    for (s = nos; s >= 1; s--) {
    printf(" ");
    }
    for (j = 1; j <= i; j++) {
    if (skip != 0) {
    if (i == 9 && j == 1) {
    continue;
    }
    }
    if (i == 1 || i == 9) {
    printf("%2c", prnt);
    }
    else if (j == 1 || j == i) {
    printf("%2c", prnt);
    } else {
    printf(" ");
    } }
    return 0; }
    int main() {
    int i, nos = 0, nosp = -1, nbsp = -1;
    for (i = 9; i >= 1; (i = i - 2)) {
    triangle(nos, i, 0);
    triangle(nosp, i, 1);
    triangle(nbsp, i, 1);
    printf("\n");
    nos++;
    nosp = nosp + 2;
    nbsp = nbsp + 2;
    }
    nos = 3, nosp = 5, nbsp = 5;
    for (i = 3; i <= 9; (i = i + 2)) {
    triangle(nos, i, 0);
    triangle(nosp, i, 1);
    triangle(nbsp, i, 1);
    printf("\n");
    nos--;
    nosp = nosp - 2;
    nbsp = nbsp - 2;
    }
    return 0;
    }
    Download Code

No comments: